14w^2+10w=0

Solution for 14w^2+10w=0 equation:

14w^2+10w=0

a = 14; b = 10; c = 0;
Δ = b2-4ac
Δ = 102-4·14·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10}{2*14}=\frac{-20}{28}
=-5/7
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10}{2*14}=\frac{0}{28}
=0
$